Assign times for transportation

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Victor Alonso RE asked Aug 14, '20 Ben Wilson commented Aug 27, '20

Assign times for transportation

Hi! I've a questions, and it's if i can assign times (as a stadistical distribution for example) for a trasportation travel?

I been usign nodes fore the transporte but i need to assign a exponential distribution for the travel times, so i'd like to know if its possible without processflow

Software Version:

FlexSim 20.2.0

flexsim 20.2.0 trasport

· 1

Ben Wilson ♦♦ commented · Aug 27, 2020 at 03:30 PM

Hi @victor_alonso.re, was matt.long's answer helpful? If so, please click the red "Accept" button on their answer. Or if you still have questions, add a comment and we'll continue the conversation.

0 ·

Answer 1 · 2020-08-15T15:09:41Z

Matt Long answered Aug 15, '20

Not sure why you wouldn't want to use Process Flow, it's a great tool once you learn how to use it.

Since you want a dynamic travel time, the speed of the transporter needs to change. If you want to keep it simple and not worry about acceleration you can use the equation:

Distance = Velocity * Time

we can solve for velocity

Velocity = Distance / Time

Now we just need to get the distance. Once you give a task sequence to the transporter, the On Receive Task Sequence trigger will fire on the transporter. You can then get the distance to travel using:

double distance = distancetotravel(current, taskSequence.tasks[1].involved1);

Based upon the set of tasks in your task sequence the tasks[i] will change.

Now you can set the speed of the transporter using

setvarnum(current, "maxspeed", distance / travelTime)

If you need to account for the acceleration and deceleration then you'll need to subtract that time from total time. Hopefully your acceleration and deceleration are constant.

Distance = Velocity * Time + 1/2 * Acceleration * Time^2 + 1/2 * Deceleration * Time^2
Velocity = Distance - 1/2 * Acceleration * Time^2 - 1/2 * Deceleration * Time ^2

Now you do the above steps and set the transporters maxspeed variable to the result of the velocity equation.

I hope this helps!

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