how to change the state of a processor?

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Daniela SA asked Aug 14, '19 Joseph Gillespie commented Aug 20, '19

how to change the state of a processor?

I am currently working on a model of a Bank in which I have two service desks. One of the objectives is to attend to all the clients even after the bank closes.

I have a Process Flow that looks like this:

My Custom Codes won't change the state of the processors and they leave them on "idle" but I want them "on break"

Software Version:

FlexSim 18.2.3

custom code

pregunta-flexsim.png (24.9 KiB)

pregunta-flexsim-1.png (131.7 KiB)

Answer 1 · 2019-08-14T17:24:44Z

Joseph Gillespie answered Aug 14, '19 Joseph Gillespie commented Aug 14, '19

@Daniela SA

Are you sure it's not working? It might be just that as soon as something gets processed, it switches back to "idle":

If you attach your model I could find out what the problem is more specifically.

statechange.gif (62.9 KiB)

· 4

Daniela SA commented · Aug 14, 2019 at 09:26 PM

@Joseph Gillespie

This is my model. It should be changing, but I don't know why it doesn't.

I run the model, and it works fine, the clients are processed but once they're gone, the state of the processors stays as "idle" and I need it to change to "on break" so it doesn't affect my pie chart for utilization.

examen-3p-process-flow.fsm

0 ·

examen-3p-process-flow.fsm (50.8 KiB)

Joseph Gillespie Daniela SA commented · Aug 14, 2019 at 10:45 PM

@Daniela SA

I'm not sure what you were doing here, but your problem is with your decide activities:

The condition you set in the decide activity is never true, so the tokens actually never make it to your custom code and thus never set the state of "Caja 1" and "Caja 2" to on break.

0 ·

capture.png (23.5 KiB)

Daniela SA Joseph Gillespie commented · Aug 14, 2019 at 10:57 PM

Yeah, I realized that. And I changed the logic already. The tokens actually make it to my custon code now but still, it wont change the state of my processors.

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