How do I know when an agv is leaving the currentCP ?

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Mark S3 asked Oct 9, '23 Joerg Vogel commented Oct 9, '23

How do I know when an agv is leaving the currentCP ?

How do I know when an agv is leaving the currentCP ? I set CP to be a resource point, and as soon as the agv leaves the CP, I release the resource

problem.fsm

Software Version:

FlexSim 22.1.4

agv controlpoint currentcp

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problem.fsm (32.9 KiB)

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Joerg Vogel commented · Oct 09, 2023 at 06:55 AM

@Mark S3, I would test any involved events by printing parameters of triggers to an output console. There are events for allocation, vehicle and control points. My test would be on vehicles traveling over a control point, stopping and resuming at or from a control point.

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Answer 1 · 2023-10-09T04:47:07Z

Jason Lightfoot answered Oct 9, '23 Felix Möhlmann edited Oct 9, '23

You can't detect this - but you can detect deallocation event.

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Mark S3 commented · Oct 09, 2023 at 05:43 AM

if I detect deallocation event,the agv need travel to next CP.It doesn't meet my needs

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Felix Möhlmann Mark S3 commented · Oct 09, 2023 at 06:05 AM

That will depend on the deallocation setting of the CP. You could configure it to coincide with the AGV moving past the control point.

If you need it to only deallocate when at the next control point, then the closest event would be the allocation of that next CP along the AGVs path. It will happen before the AGV actually drives past the current CP, but if you are not using accumulation, you can be sure that the AGV will continue past the CP in the very near future.

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Answer 2 · 2023-10-09T02:30:45Z

David Seo answered Oct 9, '23 Mark S3 commented Oct 9, '23

AGV.recentCP

Object recentCP

Description

Gets the control point that was most recently the agv's currentCP.

This is useful if the agv has moved past its last currentCP (and therefore currentCP is null) but you still want to be able to access that most recent control point.

Object cp = agv.recentCP;

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Mark S3 commented · Oct 09, 2023 at 02:45 AM

currentCP is not null,currentCP is still the same.

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