Conditional decide Verify only 2 items each shift

Question

question

Luis Gaytan asked Nov 14 2023 at 3:46 AM Luis Gaytan commented Nov 14 2023 at 3:19 PM

Conditional decide Verify only 2 items each shift

Good evening, I have the idea to verify only 2 items each shift but I want some help to improve this weak logic, the idea is that each day the operator check 2 items in the conveyor using this custom code with the conditional decide:

double currentHour = Model.dateTime.hour;
 
if (currentHour == 9)
{
return 1;
}
return 2;

Thank you for the support!

Best regards,

Luis Gaytán

Verify2Items.fsm

Software Version:

FlexSim 23.2.1

process flow conditional decide conveyor process flow

verify2items.fsm (54.4 KiB)

· 3

Felix Möhlmann commented · Nov 14 2023 at 8:44 AM

In what way do you want to improve the logic? Check items at set times each day or in a set interval? Randomize which items are checked and if so are there any constraints?

1 ·

Luis Gaytan Felix Möhlmann commented · Nov 14 2023 at 2:28 PM

good morning, to improve the logic checking just 2 items each 4 hours of the day, using flexscript.flowchart.PNG

0 ·

flowchart.png (21.9 KiB)

Felix Möhlmann Luis Gaytan commented · Nov 14 2023 at 2:40 PM

You could use a zone with a max. content of 2 and hold the tokens in there until the next 4h-period starts. Any other tokens, that can not enter are sent directly to the sink.

verify2items_2.fsm

1 ·

verify2items-2.fsm (58.9 KiB)

Answer 1 · 2023-11-14T14:55:30Z

Julio R answered Nov 14 2023 at 2:55 PM Luis Gaytan commented Nov 14 2023 at 3:19 PM

Hello @Luis Gaytan ,

Here is a different idea to do what you are trying to do. Perhaps I overcomplicated things, but it does what you are expecting.

I am using processFlow, and the verification process you can change to whererver you want. If you need any explanation of the model please let me know.

EjemploPreguntaAnswers.fsm

ejemplopreguntaanswers.fsm (54.5 KiB)

· 1

question