I'm working on a model where I have three sources (one for trays and the other two for regular lane and fast lane) and these are connected to two combiners. The combiners pack two items per tray. What I want to do is to combine two items with the same color in one tray. I have found a similar question, however in that case the pallets are colored too (Similar Question) and in my case the trays are all equal. Can anyone help me solve this problem?
In the post you linked, Jason compares the Type label on the container object with that of the item to be pulled to decide whether it can be pulled or not. You would alter this to first check if there is already an item on the tray. If so, do the same check. If not, return "1" to pull any item.
So this would one possible implementation of that in the Pull Requirement code.
- /**Custom Code*/
- Object current = ownerobject(c);
- Object item = param(1);
- int port = param(2);
- if(port == 1) {
- // Pull any tray
- return 1;
- }
- if(current.first.subnodes.length > 0) {
- // If there is an item on the tray, type must match
- return current.first.first.Type == item.Type;
- }
- else {
- // Pull any item if tray is empty
- return 1;
- }
11 People are following this question.
FlexSim can help you understand and improve any system or process. Transform your existing data into accurate predictions.
FlexSim is a fully 3D simulation software environment. FlexSim can be used to simulate any process in any industry.
FlexSim®, FlexSim Healthcare™, Problem Solved.®, the FlexSim logo, the FlexSim X-mark, and the FlexSim Healthcare logo with stylized Caduceus mark are trademarks of FlexSim Software Products, Inc. All rights reserved.
May we collect and use your data?
Learn more about the Third Party Services we use and our Privacy Statement. May we collect and use your data to tailor your experience?
Explore the benefits of a customized experience by managing your privacy settings for this site or visit our Privacy Statement to learn more about your options.
