delay on message open close ports

Question

question

Carlos SR asked Jul 23, '20 Carlos SR commented Jul 23, '20

delay on message open close ports

i want to close the input on the queue instead of release item and open it when the queue after that

delay.fsm

Software Version:

FlexSim 20.1.3

flexsim 20.1.3 condition

delay.fsm (16.0 KiB)

· 2

Matt Long commented · Jul 23, 2020 at 04:58 AM

I'm not sure I'm quite following what you want to do. Are you wanting to hold specific items in the queue and later release them to Queue2? Or do you want items at certain intervals to enter Queue2?

0 ·

Carlos SR commented · Jul 23, 2020 at 12:38 PM

@matt.long,

i want the delay of the 90 seconds if it happens to input close the port and then when that item who had stayed 90 seconds on exit input open the port

0 ·

Answer 1 · 2020-07-23T15:15:15Z

tannerp answered Jul 23, '20 Carlos SR commented Jul 23, '20

@carlos.sr,

You could accomplish this with a Processor that has a Process Time of 90 seconds and a Max Content of 1. Or you could accomplish this with Process Flow. But, I understand that you're using a queue, so I created an example model that uses a queue with triggers. The On Entry trigger closes the input/output ports and then sends a delayed message. After 90 seconds of delay, the message is received and the On Message trigger is fired, which opens the input/output again.

I hope this helps. Let me know if you have questions.

staytime 90 seconds.fsm

input-close.png (11.9 KiB)

staytime-90-seconds.fsm (147.7 KiB)

· 1

Carlos SR commented · Jul 23, 2020 at 09:27 PM

now the only item stay 90 seconds but i want to close the port when the staytime reaches that value and open it when that item exit the queue

0 ·

Answer 2 · 2020-07-23T21:26:19Z

Carlos SR answered Jul 23, '20

now the only item stay 90 seconds but i want to close the port when the staytime reaches that value and open it when that item exit the queue

question