Good morning, I want to consult without the need to use process flow, how do I so that when the processor is on break or lunch it does not have a box in service? As seen in the image.
Thank you for your attention.
how to configure the processor
FlexSim 22.2.1
Hi @Paulina B6, was one of Joerg Vogel's or Sri_vikas K's answers helpful? If so, please click the "Accept" button at the bottom of the one that best answers your question. Or if you still have questions, add a comment and we'll continue the conversation.
If we haven't heard back from you within 3 business days we'll auto-accept an answer, but you can always unaccept and comment back to reopen your question.
The Tool Timetable stops an involved object.
You need instead two actions. You close the input, no more new items items are allowed to enter. You set a label value in your involved processor, which you check OnExit of a processed item to stop the processor. Also On Exit Event you open the input again.
please be aware of a situation on break for lunch, that you must stop the processor, if it doesn’t process an item. You check this by its subnodes length.
[involved object].subnodes.length
hello @Joerg Vogel, Can you give me an example of this, please? Thank you
Hi @Paulina B6
One Idea I could give is give the timetable for the queue just less than 5 seconds less than processors. so that queue will stop giving the output to the processors before the processor gets into stop state. Refer the model below to understand the idea clearly.
hi @Sri_vikas K
I was trying to review your recommendation, however, since I have a previous version 22.2.1 it won't let me open it.
I do not know if there is any way to be able to see it, I am attentive.
The description is enough (also see the documentation) - the idea is that you stop before the lunch period to ensure that it's empty when the break begins. Another approach is to only pull items that you can finish before the next break - information that can be gleaned from the timetable and its events.
15 People are following this question.
