I read that the objectexists is deprecated and to use treenode.rank instead.
How do I have to do it correctly? I'm not sure I'm doing it in the correct way.
If I do like this I get an exception when object does not exist:
Object box = item.first; if (box.rank) box.color = Color(1,0,0);
The treenode.rank line is a copy-paste mistake. If the object doesn't exist the variable should be null and so you just put the variable into an if statement.
Object box = model().find("Queue1").first;
if(box)
box.color = Color.red;
And how does this work, if I want to know if a Label exists?
You would need to get a reference to the label node:
if(box.labels["myLabel"]) box.color = Color.red;
Similar to @Matthew Gillespie's comment, you could also use:
if(box.myLabel?)
box.color = Color.red;
Using the ? in this case would give you slightly different behavior depending on what the value of the label is:
//myLabel = 0 if(box.labels["myLabel"]) //true if(box.myLabel?) //false //myLabel = 1 if(box.labels["myLabel"]) //true if(box.myLabel?) //true //myLabel doesn't exist if(box.labels["myLabel"]) //false if(box.myLabel?) //false
Would this be ok to use, if looking for a label "MyLabel" on Queue1 in the model? Or is there a better way?
treenode thelabel = model().find("Queue1>labels/MyLabel");
if(thelabel)
return thelabel.value;
If you just want to get the value of the label if the label exists there is an easier way to do this using the ? operator:
return model().find("Queue1").MyLabel?;
Your code works, but the preferred way to get a label node is using the labels property:
treenode thelabel = model().find("Queue1").labels["MyLabel"];
seems I am too stupid to figure this out by myself: Attached is a model as a sample. OnEntry of the Queue, I create a label MyLabel with the value of "1" on 50% of all items. On sendtport of that Queue, I want to send the item through the label value's port number ("1"), if the label exists and through port 2, if it does not exist.
Everything I tried does not work or throws an exception, because the label does not exist.
Can you please help me (and @christoph gruber) here?
Thanks
Sorry, but I do not understand exectly:
//myLabel doesn't exist
if(item.labels["myLabel"] == 0){
msg ("Info", "Label myLabel doesen´t exist!");
}
This code does not work in 17.03 - it only works in 17.1!
But why doesn´t work the code below in 17.1?
@Ralf Gruber ; @Matthew Gillespie
//myLabel exist
if (item.labels["CControl"] == 1){
msg ("Info", "Label myLabel exist!");
}
You shouldn't be comparing the label node to 0 or 1. If the label does exist it will return a valid treenode (which doesn't equal 1 or 0) and if it doesn't exist it will return nullvar (which also doesn't equal 1 or 0). So your code examples should look like this:
//myLabel doesn't exist
if(!item.labels["myLabel"]){
msg ("Info", "Label myLabel does not exist!");
}
//myLabel exist
if (item.labels["myLabel"]){
msg ("Info", "Label myLabel exists!");
}
I am getting invalid exception error for the following code.
Object Box = current.subnodes[2];
if(Box)
{
current.color = Color.black;
}
Also see the attached model. The code is written in the process finish trigger of the processor.
Have you checked that the current node actually has two subnodes?
if(current.subnodes.length >= 2)
{
Object box = current.subnodes[2];
current.color = Color.black; // Did you mean: box.color = .. ?
}
Hi Misha,
Thanks for the reply, your code will help.
The current doesn't have two sub nodes, only one. Conceptually, objectexists condition using
if(current.subnodes[2])
{
current.color = Color.black;//I meant current.color only
}
shouldn't throw an exception right?
Regards,
Arun KR
11 People are following this question.
© 1993- FlexSim Software Products, Inc. All Rights Reserved.
FlexSim is a fully 3D simulation software environment. FlexSim can be used to simulate any process in any industry.
FlexSim®, FlexSim Healthcare™, Problem Solved.®, the FlexSim logo, the FlexSim X-mark, and the FlexSim Healthcare logo with stylized Caduceus mark are trademarks of FlexSim Software Products, Inc. All rights reserved.
