How to route a part between two consecutive stations in a line with some logic?

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Anivesh K asked Feb 5, '19 Anivesh K commented Mar 4, '19

How to route a part between two consecutive stations in a line with some logic?

Problem Description:

Suppose a part from source reaches at station 1, it will continue its task at station 1 until:

1) another part approaches station 1 from the source. In this case part will move to station 2 to complete its remaining task. And the part will complete its remaining task at station 2 move to sink via Queue.

"or"

2) if the task is completed at station 1 itself, part will go directly to sink via Queue.

Kindly suggest me better logic for this situation..!!

Software Version:

FlexSim 18.2.2

routing logic distributed work

problem-model.fsm (41.2 KiB)

· 3

5 |100000

Attachments: Up to 12 attachments (including images) can be used with a maximum of 23.8 MiB each and 47.7 MiB total.

Jeff Nordgren commented · Feb 05, 2019 at 07:39 PM

@Anivesh K

What is the difference between a part that would finish at station 1 as opposed to a part that needs to go to station 2? Is is a certain type of part? Do you know ahead of time which parts or which part types complete at station 1? I'm not sure what "task" you are referring to that needs to "finish". What does that task include? I guess what I'm saying is that some more details would be very helpful.

Thanks.

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Joerg Vogel commented · Feb 07, 2019 at 05:36 AM

@Anivesh K, can you give me an example, what product can be processed like you describe? I am just curious. I have in mind a logic built on ProcessFlow that preempts a delay activity at station 1 when an item enters at a queue or fires at a photoeye.

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Anivesh K Joerg Vogel commented · Feb 07, 2019 at 05:54 AM

@Jörg Vogel lets us assume it is a part which needs cleaning activity, which can take place at both station 1 and station 2 ,(Both stations are capable of doing the same activity). so movement of part will be dependent on the incoming parts from source ( generated randomly) "or" the time it need to complete the cleaning activity. Hope it clears, let me know otherwise.

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Answer 1 · 2019-02-07T11:44:59Z

Joerg Vogel answered Feb 7, '19

This model is a partly result. There are some conditions that you must accept or change the logic. The items need more time to reach the station before you evaluate another waiting item at the restriction zone border. You can set a label at the station and evaluate it when an item arrive and let it directly pass the first station. This isn't inside of the model. The process time is dependend of a label value of the item and partly of the process time of the first station. The item is processed for the time another item witing at the photoeye to reach the station. After that short time the item is only stopped at the station 1 to be resumed when an item reaches the photoeye. Also there is missing a condition when an item at station 2 leaves that the item at station 1 resumes, too.

problem-model-jv.fsm

problem-model-jv.fsm (43.7 KiB)

5 |100000

Attachments: Up to 12 attachments (including images) can be used with a maximum of 23.8 MiB each and 47.7 MiB total.

Answer 2 · 2019-02-05T19:55:47Z

Jeff Nordgren answered Feb 5, '19 Jeff Nordgren commented Feb 6, '19

@Anivesh K

Attached is your model with the changes that I've made. Basically, I added 2 labels to each part in the Source. Then, in station 1, if the Type of the part is a 1, that means that it completes it's "task" in station 1. If the part Type is 2, then it will move on to station 2 where it will complete processing.

I'm not sure if this is what you had in mind or not. If this is not what you were looking for then please give us a few more details of how it is supposed to work.

Thanks.

problem-model-jn1.fsm

problem-model-jn1.fsm (147.1 KiB)

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5 |100000

Attachments: Up to 12 attachments (including images) can be used with a maximum of 23.8 MiB each and 47.7 MiB total.

Anivesh K commented · Feb 06, 2019 at 05:08 AM

@Jeff Nordgren please find below details:

1) Both station 1 and station 2, is capable of doing the same work. (Basically both are same stations connected in series )

2) there is no such rule that part A will have work only at station 1 or station 2, its movement is entirely dependent upon the completion of its task time or any part approaching from source.

example. if part A has total task time of 10 min, and it starts processing at station 1, then we have 2 conditions:

a) another part approaches station 1 after 3 min, in that case part A will move to station 2 to complete remaining job of 7 min (10-3 min)

"or"

b) if no part approaches station 1 in that time period, part A will complete its process time of 10 min at station 1 itself and will move to sink via station 2 (without spending anytime at station 2) and queue.

**consider task time same as processing time at stations.

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