Check if all members in group are busy

Question

question

ana.pc2 asked Jun 4, '20 Braydn T commented Jun 4, '20

Check if all members in group are busy

Hello!

I was wondering how to check the status of all members in a group, so I can send the item to a different port if all are busy. For example:

Object item = param(1);
Object current = ownerobject(c);

/**Conditional Port*/

treenode stations = Model.find("Tools/Groups/SB_Group");

if (stations.stats.state().value == STATE_BUSY)
{
    return 2;
}
else
{
    return 1;

}

Thanks for the help!

Software Version:

FlexSim 20.1.1

flexsim 20.1.1 send to port status

· 1

ana.pc2 commented · Jun 04, 2020 at 11:07 AM

I think this is working (?):

treenode stations = Model.find("Tools/Groups/SB_Group");

if (stations.as(Object).stats.state().value == STATE_BUSY)
{
    return 2;
}
else
{ ...

But then I get the following error:

time: 73.664834 exception: FlexScript exception: Could not access state variable on object SB_Group (profile: NULL) at ...

0 ·

Answer 1 · 2020-06-04T11:20:42Z

Steven Hamoen answered Jun 4, '20 Braydn T commented Jun 4, '20

@Ana PC2 Please check out the group class. To go through every member of a group you can use an index. So in your case

for(int 1 = 1; i <= Group("SB_Group").length; i++)

{

Object station = Group("SB_Group")[i];

etc...

}

· 5

ana.pc2 commented · Jun 04, 2020 at 11:29 AM

Hi @steven.hamoen!

Thanks for your help, but I need to know if all at the same time are busy, then I will send to port 2. If any of all the stations are idle, I want to send to port 1.

I thought about doing a counter, if that station is busy, add 1, once I checked all stations, if that number == lenght of stations on that group, then send to port 2.. but it doesn't work properly...

I leave the code here:

Variant counter = 0;

for(int i = 1; i <= Group("SB_Group").length; i++)
{
    Object station = Group("SB_Group")[i];
    if (station.stats.state().value == STATE_BUSY)
    {
        counter += 1;
    }
}
if (counter == Group("SB_Group").length)
{
    return 2;
}
else
{ ...

Thanks!

0 ·

Braydn T ana.pc2 commented · Jun 04, 2020 at 12:55 PM

@Ana PC2 That looks like it would work to me. What does not work?

0 ·

Steven Hamoen commented · Jun 04, 2020 at 12:55 PM

Hi @Ana PC2 Code looks ok. But you say it doesn't work properly. What exactly doesn't it do? And have you tried stepping through the code with the debugger? That way you can see what happens exactly.

0 ·

ana.pc2 commented · Jun 04, 2020 at 01:07 PM

Hi @steven.hamoen and @Braydn T, so it looks like the problem was in:

(station.stats.state().value == STATE_BUSY)

But I changed it to: .subnodes.length > 0 and now it is working... It is a combiner, not a processor, should it matter?

That step now sends things correctly, but then on the next process which I am doing something similar, the simulation stops, and I get:

FlexScript exception: Invalid down cast. Object is not an instance of the target type. at MODEL:/Entrada_B>variables/sendtoport

"Entrada_B" is a Source.... I am trying to fix it but I don't really understand what the issue is... any ideas??

Thanks again!!

0 ·

Braydn T ana.pc2 commented · Jun 04, 2020 at 01:15 PM

I don't think a source has a busy state. Only generating and blocked.

1 ·

question