How can I "delete" the elements on the processor when there's a breakdown?

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Felipe G asked Nov 27, '20 Jason Lightfoot answered Nov 30, '20

How can I "delete" the elements on the processor when there's a breakdown?

I've got a model that it has a breakdown for 1 hour, but the element on processing, stills there counting TimeInSystem. Is there some way that this element go directly to a sink of elements don't processed, I'm trying with a Trigger applying an OnStop . I'm using a list flow there the elements wait in queue a certain time to be process, there is a maximum to wait, if it occurs this maximum they go to a sink, but if it's processing go to another sink. My idea is when there's a breakdown, the processor doesn't have items on it. Hope someone tell me what I can do. Thanks.

Software Version:

FlexSim 20.0.8

processflow processors flexsim 20.0.8 breakdowns

· 1

Joerg Vogel commented · Nov 28, 2020 at 08:00 AM

@Felipe G, can you please attach a model or an example, because depending on your setup the answer will be different. A 3D model logic processor creates events and and you have to cope with them when you move an item in a break down. A “process flow” driven processor has viewer created events or none. Then you can move or delete an item, because there are much lesser hidden dependencies in FlexSim system logic.

0 ·

Answer 1 · 2020-11-30T00:38:54Z

Jason Lightfoot answered Nov 30, '20

In the MTBF/MTTR trigger "OnBreakDown" you can put something like this code snippet which assumes there's one item in a processor.:

if(content(involved)) {
    destroyeventsofobject(involved,0,0,NULL,involved.first);
    moveobject(involved.first,Model.find("Queue2"));
}

Example model attached.RemoveItemOnFailure.fsm

removeitemonfailure.fsm (124.6 KiB)

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