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Eric C2 avatar image
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Eric C2 asked Jeanette F commented

separator two ways to unload

Hi All,

I'm creating my model and at the end of the separator I want that the crane unload the items with label type 1 and 2 (boxes) and the other item with label type 3 (pallet) don't use the crane to be unload in the next queue.

I try to solve this but the crane unload all the items.

I add this to the script saying that the crane just unload items 1 and 2 but it has not effect.

Someone knows how I have to add to reach this??

I add the model, so you can see better why I'm saying. At the end I don't want that the pallet to be unload by the crane, this item don't need transport.

prueba.fsm

Thank you in advance.

FlexSim 21.0.1
flexsim 21.0.1separator unload
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prueba.fsm (32.5 KiB)
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Jeanette F avatar image Jeanette F ♦♦ commented ·

Hi @Eric C2, was Roi Sánchez's answer helpful? If so, please click the red "Accept" button at the bottom their answer. Or if you still have questions, add a comment and we'll continue the conversation.

If we haven't heard back from you within 3 business days we'll auto-accept an answer, but you can always unaccept and comment back to reopen your question.

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1 Answer

Roi Sánchez avatar image
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Roi Sánchez answered Jeanette F commented

Hi @Eric C2, I guess your conditional sentence is not right. You must do the following:

if (item.Type == 1 || item.Type == 2)


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Eric C2 avatar image Eric C2 commented ·

Ok, thank you, but if I do that then the item type 3 is not unload from the separator.

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Jeanette F avatar image Jeanette F ♦♦ Eric C2 commented ·

Hello @Eric C2,

I would use conditional transport. This will allow the crane to transport the specified item types, but then the other type will go to the output port without transport.


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1610997398742.png (69.1 KiB)