question

Since there are not that many groups you could simply create one sequence parameter for each and offset the assigned numbers in the "On Set" code. So the first group would be assigned the numbers from 1 to 38, the next from 39 to 95 and so on.

If you want to only use the one parameter, you can sort the table by building, floor and then order number. This will keep each group together but ordered according to the sequence parameter. Afterwards, the order numbers are reassigned as the current row number of each entry. Finally, the table is then restored to the original row ordering by using a newly created column that stores the original row numbers. (Otherwise the next time the order is changed, the resulting order would depend on the previous one)

Table arrivals = Table("Arrivals");
// Sort the groups by assigned order
arrivals.sort([5, 6, 8]);
// Reassign order numbers
for(int row = 1; row <= arrivals.numRows; row++)
{
    arrivals[row][8] = row;
}
// Sort back into original configuration
arrivals.sort(20);

Both options should work, though I presume the optimizer might fare a little better with the first option, since the order of each group is determined independently from each other.

layout-v32-13-fm.fsm