Why conveyor.size.y returns the half of the y size of a conveyor?

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Sebastian Hemmann asked Mar 9, '17 Phil BoBo edited Mar 16, '17

Why conveyor.size.y returns the half of the y size of a conveyor?

I´ve tryed to figure out why the method .size.y returns the half of the Conveyors width but the full size of all other objects.

Software Version:

FlexSim 17.0.2

conveyor translate item .size.y

· 1

Sam Stubbs ♦ commented · Mar 09, 2017 at 03:00 PM

Interesting. It could be that this is unintended or there may be a reason for it, I'll ask the developers if they are aware of this. I suppose for now, just take the half size into consideration for your model.

0 ·

Answer 1 · 2017-03-16T16:43:29Z

Phil BoBo answered Mar 16, '17 Phil BoBo edited Mar 16, '17

.size.y returns the value of the spatialsy attribute of the conveyor. Conveyors set that value to half of their width. Their spatialy attribute is set to the center of the conveyor's starting point. This is how the conveyor's spatial values were purposefully designed.

In 17.1, we added a Conveyor class that has a width property where you can access the conveyor's width directly:

Conveyor conveyor = model().find("Conveyor1");
return conveyor.width;

conveyor-spatialsy.png (84.3 KiB)

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