Why does TaskExecuter Class have beginOffsetDefault() method?

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Yokota T asked May 10, '23 Yokota T commented May 11, '23

Why does TaskExecuter Class have beginOffsetDefault() method?

Hello all,

I am currently reading the Module Development page.

However, I do not understand why the TaskExecuter class has two methods, beginOffset() and beginOffsetDefault().

As shown in the code below, it appears that beginOffsetDefault() is provided to override beginOffset() and hook a specific process.

double MyTaskExecuter::beginOffset(double endspeed, treenode item)
{
    if (xOnly) {
    offsetloc[1] = 0;
    offsetloc[2] = 0;
    }

    return beginOffsetDefault(endspeed, item);
}

However, I am not sure how it differs from "return __super::beginOffset();"

Thank you in advance for your assistance.

Software Version:

FlexSim 23.1.1

module sdk dll

Answer 1 · 2023-05-10T16:55:18Z

Jordan Johnson answered May 10, '23 Yokota T commented May 11, '23

The beginOffsetDefault() function causes "normal" offset travel to occur. By defining this as a function, we are able to avoid repeating code. The TaskExecuter, Operator, Transporter, and Elevator all call this function.

The difference between this function and calling __super::beginOffset() is that TaskExecuter::beginOffset() sometimes modifies the z component of the travel destination. Not all sub classes need that modification, but they do need the rest of the logic in beginOffsetDefault().

Suppose you override the Operator class. Your MyOperator::beginOffset() method, you cannot call __super::beginOffset(), because that would call Operator::beginOffset(), not TaskExecuter::beginOffset(). By creating the beginOffsetDefault() method, base classes can call that method without worrying about any logic added by intermediate classes.

· 1

Yokota T commented · May 11, 2023 at 04:58 AM

Thank you for your reply. I understand now. I only considered the case where the inheritance relationship is simple.

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